Series Circuit Parallel Circuit Series and Parallel Circuit Joule's Law and Power Chapter Quiz

(Series Circuit)

The total voltage is the sum of the voltage on each component. eq 1: V_{0} = V_{1}+ V_{2} + V_{3 }+...+ V_{n }(In this case, V_{T} = V_{1}+ V_{2})

The total resistance is equal to the sum of the resistance on each component._{ }eq 2: R_{0} = R_{1} + R_{2} + R_{3} +...+ R_{n} (In this case, R_{T} = R_{1} + R_{2})

The total current is equal in every component. eq 3: I_{0} = I_{1} = I_{2}= I_{3}= I_{4} =...= I_{n }(In this case, I_{T} = I_{1} = I_{2})

First, we have to find out the total voltage using equation 1 above, and then resistance using equation 2, and finally you can find out the current using equation 3.

Total voltage is 9 + 1 + 16 + 4 = 30 V Total resistance is 30 + 10 + 40 + 20 = 100 ohm

What is the current on A and B? ( e.g. "1 A" )

A -

B -

What is the voltage on A, B and C? ( e.g. "1 V" )

C -

What is the resistance on C? (e.g. "1") ohm

What is the total resistance? (e.g. "1") ohm

What is total current? ( e.g. "1 A" )

(Parallel Circuit)

The resistance is equal to the sum of resistance on each component divided by the product of resistance of each component. eq 5: 1/R_{0} = 1/R_{1} + 1/R_{2 }+...+ 1/R_{n }(In this case, 1/R_{T} = 1/R_{1} + 1/R_{2})

The total current is equal to the sum of current in each component. eq 6: I_{0}= I_{1} + I_{2} + I_{3} + I_{4} +...+ I_{n }(In this case, I_{T} = I_{1} + I_{2})

In order to find out the total voltage, we have to find out the total resistance. Using equation 5, we can find out the total resistance. 1/R = 1/15 + 1/15 + 1/30 = 5/30, R = 6 ohm

Using equation 4, we now know the voltage on A, B, and C, which is 30 V each. Using ohm's law again, we can find out the current on A, B, and C.

I_{A} = 30/15 = 2 A, I_{B} = 30/15 = 2 A, I_{C} = 30/30 = 1 A .

When you add up all the current (using equation 6), we get 5 A which is the total current.

What is the voltage on A, B and C? What is the current on A, B, C, and D?

Total Resistance ( e.g. "1" ) ohm

Total Voltage ( e.g. "1 V" )

Total Current ( e.g. "1 A" )

Voltage on ( e.g. "10 V" )

Current on ( e.g. "0.1 A" )

D -

The total voltage is the voltage of series plus the voltage of parallel. eq. 7: V_{T} = V_{1} + V_{2} = V_{1} + V_{3}

The total resistance is the resistance of series plus the resistance of parallel. eq. 8: R_{T} = R_{1} + [(R_{2}R_{3}) / (R_{2} + R_{3})]

The total current is equal to the current on series and to the sum of the current of parallel circuit.

eq. 9: I_{T} = I_{1} = I_{2} + I_{3}

First of all, we have to look at the diagram very carefully (The order of the questions also help us from where we have to start). Using equation 4, we know that the voltage on D is equal to C, which is 80 V. We also know A and B have the same voltage. Using the voltage law, we can find out the voltage on A and B, which is 230 - 80 = 150 V each.

Now we get all the voltages on each component. Using ohm's law, we can find out the current on A, B, C, and D. I_{A}= 150/30 = 5 A; I_{B} = 150/30 = 5 A; I_{D} = 80/40 = 2 A; I_{C} = 10-2 = 8 A. The sum of the current on A and B is equal to that of C and D (eq. 3). A+B = C+D.

H = I^{2}Rt

where:

You can convert joule to calories by multiplying 0.24 on joule.

In a parallel circuit, the least resistance draws the most current and produces the most heat energy because larger current flows through that component.

P = VI = I^{2}R = V^{2}/R

Power [W] = work (energy) / time [t] (unit of work is joule [J] and time[t] is in second).

Therefore,

work or energy [joule] = power [W] * time [t].

The unit for energy is watt-second; watt-minute; and watt-hour.

1 watt-second = 1 joule

First, we have to find out the total resistance, and then the tatal potential difference (voltage). Total resistance is R = 60/3 = 20 ohm.(eq.5) And total potential difference is V= 20 * 2 = 40 V.(V=I*R) Now, we can find current on A and B. I_{A} = 40/30 = 4/3 A and I_{B} = 40/60 = 2/3 A.

Power comsumption P_{A} = (V*I) = 40 * 4/3 = 160/3 (53.3) watts; P_{B} = 40 * 2/3 = 80/3 (26.7) watts.

The heat energies are H_{A} = I^{2}Rt = (4/3)^{2} * 30 * 10 = 1600/3 (533.3) J; H_{B} = (2/3)^{2} * 60 * 10 = 800/3 (266.7) J.

Try Chapter 14 Quiz and see how much you learned.

[Ch 11] - [Ch 12] - [Ch 13] - [Ch 14] - [Ch 15]